[Bf-committers] Matrix "differencing" procedure

[Martin Poirier]

RA = B

You're looking for R.

RiAA = BiA (where iA is inverse of A)

R(iAA) = BiA

R(I) = BiA (where I is the identity matrix)

R = BiA


You'll need Mat4MulMat4 and Mat4Invert from arithb.c

Hope that's useful.

Martin

--- Roland Hess <me@harkyman.com> wrote:

> Almost have my pinbone feature working, and there's
> one more thing I 
> would like some advice on.
> 
> I have two 4x4 matrices (MatA, and MatB). I want to
> find the matrix 
> (MatR) that will transform MatA into MatB. Right
> now, I'm thinking I 
> need to do this:
> 
> 1. Find inverse matrix of MatA (IMatA)
> 2. Multiply MatB by IMatA, giving MatAB
> 3. Find inverse of MatAB
> 
> The result of step 3 should be what I'm looking for
> (MatR), right? In 
> other words, multiplying MatB with MatR will
> generate MatA.
> 
> Roland Hess - harkyman
> 
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>
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